2014 Santaizi ATP Challenger – Doubles

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Doubles
2014 Santaizi ATP Challenger
Final
ChampionAustralia Samuel Groth
Australia Chris Guccione
Runner-upUnited States Austin Krajicek
Australia John-Patrick Smith
Score6–4, 5–7, [10–8]
Events
Singles Doubles
Santaizi ATP Challenger · 2015 →

This was the first edition of the tournament.

Samuel Groth and Chris Guccione won the title, defeating Austin Krajicek and John-Patrick Smith in the final, 6–4, 5–7, [10–8].

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 Australia S Groth
Australia C Guccione
77 77
Australia J Millman
Australia L Saville
65 62 1 Australia S Groth
Australia C Guccione
6 6
Japan H Moriya
China D Wu
6 6 Japan H Moriya
China D Wu
1 4
WC Chinese Taipei Ho Chih-jen
Chinese Taipei J-c Hung
3 3 1 Australia S Groth
Australia C Guccione
6 65 [10]
3 Thailand Sa Ratiwatana
Thailand So Ratiwatana
6 6 Switzerland M Chiudinelli
Japan T Ito
2 77 [6]
Chinese Taipei C-f Wang
Israel A Weintraub
4 4 3 Thailand Sa Ratiwatana
Thailand So Ratiwatana
65 4
Switzerland M Chiudinelli
Japan T Ito
6 5 [10] Switzerland M Chiudinelli
Japan T Ito
77 6
WC United States J Jung
Chinese Taipei Yang Shao-chi
0 7 [6] 1 Australia S Groth
Australia C Guccione
6 5 [10]
Slovakia K Beck
Slovakia L Lacko
6 3 [10] 2 United States A Krajicek
Australia J-P Smith
4 7 [8]
Chinese Taipei L-c Huang
Japan Shuichi Sekiguchi
3 6 [7] Slovakia K Beck
Slovakia L Lacko
2 3
Chinese Taipei H-y Peng
Chinese Taipei T-h Yang
6 4 [8] 4 Japan T Matsui
United States R Ram
6 6
4 Japan T Matsui
United States R Ram
2 6 [10] 4 Japan T Matsui
United States R Ram
4 3
United Kingdom J Delgado
Luxembourg G Müller
6 6 2 United States A Krajicek
Australia J-P Smith
6 6
WC Chinese Taipei Chuang Ting-yu
Chinese Taipei C-y Yu
1 4 United Kingdom J Delgado
Luxembourg G Müller
4 65
Chinese Taipei T Chen
Japan G Soeda
5 1 2 United States A Krajicek
Australia J-P Smith
6 77
2 United States A Krajicek
Australia J-P Smith
7 6

References[edit]