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English: An arithmetic coding example assuming a fixed probability distribution of three Symbols "A","B" and "C".

An arithmetic coding example assuming a fixed probability distribution of three Symbols "A","B" and "C". Probability of "A" is 50%, probability of "B" is 33% and probability of "C" is 17%. Furthermore we assume that the recursion depth is known in each step. In step one we code "B" which is inside of the interval [0.5,0.83): The binary number "0.10x" is the shortest code that represents an Interval that is entirely inside of [0.5,0.83). "x" represents here an arbitrary bit sequence. There are two extreme cases: the smallest x stands for an infinite number of zeros which represents the left side of the represented Interval. Then the left side of the Interval is dec(0.10)=0.5. The greatest x stands for an infinite number of ones which gives a number that converges towards dec(0.11)=0.75 Therefore "0.10x" represents the Interval [0.5,0.75) which is inside of [0.5,0.83)

Now we can leave out the "0." part since all Intervals begin with "0." and we can ignore the x because no matter what Bit-sequence it represents, we will stay inside of [0.5,0.75)
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Author Evolution124

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Date/TimeThumbnailDimensionsUserComment
current22:08, 30 October 2023Thumbnail for version as of 22:08, 30 October 20231,052 × 744 (41 KB)PhlosioneerFixed typo in bottom-left: 0.11011 becomes 0.110011
13:49, 28 May 2012Thumbnail for version as of 13:49, 28 May 20121,052 × 744 (49 KB)Evolution124{{Information |Description ={{en|1=An arithmetic coding example assuming a fixed probability distribution of three Symbols "A","B" and "C". Probability of "A" is 50%, probability ob "B" is 33% and probability of "C" is 17%. Furthermore we assume tha...
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